Solving Radical Equations
This post about solving radical equations is part of a series of posts to help you prepare for the Advanced Algebra and Functions part of the Accuplacer test.
Does the equation have a real solution? If so, what is it?
This kind of equation is called a radical equation, because it contains a radical — in this case, a square root.
Let’s try to solve this radical equation:
Subtract 5 from each side:
The square root of something equals something negative? Really? The definition of square root specifies that it means a positive number. But this square root is supposed to equal something negative.
No real solution.
You may be tempted to keep going from
and see what happens. OK, let’s try that. Follow the usual steps for solving a radical equation:
- Isolate the radical. We did that above when we added 10 to each side.
- Square both sides:
- Subtract 3 from each side:
- Divide by 4:
There’s a solution: . Now let’s see if it works. Substitute back into the left-hand side of the original equation. You should get:
That simplifies to:
So what looked like the wrong way was indeed the wrong way, the solution does not work, and the answer to the question is No, the equation does not have a real solution.
This question is similar to question number 14 in the sample questions for the Accuplacer Advanced Algebra and Functions test.
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