Finding a Line’s Equation from the Graph of Its Perpendicular
This post about finding the equation of a line that is perpendicular to a line you read from a graph is part of a series of posts to help you prepare for the Advanced Algebra and Functions part of the Accuplacer test.
Find the equation of the line that goes through the origin and is perpendicular to the blue line shown.
The origin is the point on the coordinate plane with the coordinates .
You are asked to find the equation of the line that is perpendicular to the one shown and passes through the origin.
How do you find the equation of a perpendicular line? Start with the slope: If two lines are perpendicular and their slopes are and , then . One is the negative reciprocal of the other. Another way to say this: .
Next, find , the slope of the line shown. Then the slope of the line whose equation we seek equals .
To do that, choose two points with coordinates you can read. The intercepts — (-2, 0) and (0, -2) — suggest themselves. The slope of the line between those points is the difference between their y-values divided by the difference between their x-values. The difference in y-values is . The difference in x-values is . Then the slope of the line between the points is:
So the original line has a slope . Then the line we are looking for has a slope .
From there, all we need for the line’s equation is the y-intercept. You’re told the line passes through the point (0, 0), so the y-intercept — the b in — is 0.
A line that passes through the origin has a y-intercept of 0.
Then this line’s y-intercept is 0 and its equation is
That’s the brown line on the graph below.
The brown line looks perpendicular to the blue one and goes through the origin. Looks about right.
For more about relating a line’s equation to its graph, see “Comparing Data in Different Formats.”
This question is similar to question number 2 in the sample questions for the Accuplacer Advanced Algebra and Functions test.